Last new content was learned and applied today in class.

Surface area of a sphere is 4 times Pi times r^2.

In other words, 4 of the largest circles from cross-sections of a sphere would cover the sphere completely.

But a hemisphere has a base, so its surface is 3 times Pi times r^2.

HW #14: p 457: 1-6, and p 544:8,9,12-14. Show work and use of formulas.

On B day we practiced degrees, radians, & coordinates for a point on the unit circle.

Warm-up was p 532: 1 & 8.

We checked homework and showed lots of work as the homework was fairly difficult (HW #13).

I took a grade on HW #12 & #13 - 4 pts each.

Then we took the Unit Circle Quiz - 24 pts and worked on the new homework for the rest of class.

Attached: answers to HW #13 from the board.

Surface area of a sphere is 4 times Pi times r^2.

In other words, 4 of the largest circles from cross-sections of a sphere would cover the sphere completely.

But a hemisphere has a base, so its surface is 3 times Pi times r^2.

HW #14: p 457: 1-6, and p 544:8,9,12-14. Show work and use of formulas.

On B day we practiced degrees, radians, & coordinates for a point on the unit circle.

Warm-up was p 532: 1 & 8.

We checked homework and showed lots of work as the homework was fairly difficult (HW #13).

I took a grade on HW #12 & #13 - 4 pts each.

Then we took the Unit Circle Quiz - 24 pts and worked on the new homework for the rest of class.

Attached: answers to HW #13 from the board.

answers_to_hw_13.pdf |